121x^2+220x+100=0

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Solution for 121x^2+220x+100=0 equation:



121x^2+220x+100=0
a = 121; b = 220; c = +100;
Δ = b2-4ac
Δ = 2202-4·121·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-220}{242}=-10/11$

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